Negative feedback

Outline of the problems

We will model the temperature in an apartment that is being heated by a thermostat–controlled heater/cooler. This system has been designed to attempt to drive the temperature to one specified target value $T_c$. In each setup the time dependence of the temperature will be governed by a system of differential equations, and we will address the following
Basic questions

Single room

Consider a one–room apartment with a heater/cooler, and a thermometer. The thermometer is coupled to the heater cooler in such a way that it will activate the heater when the temperature $T$ is below the target value $T_c$, while it will activate the cooler when the temperature is above $T_c$.

A very simple model for this is to assume that the heat production of the heater/cooler is proportional to $T-T_c$, and that by Newton's cooling law the rate of change of the temperature of the room is also proportional to $T-T_c$. This leads to a differential equation \begin{equation} \frac{dT}{dt} = -\kfb (T-T_c) \label{eq:one-room-ode} \end{equation} where $\kfb$ is the feedback rate.

Problem 1. Answer the basic questions for this one room apartment.

Double room

Consider a two room apartment with a heater/cooler in the living room, and a thermometer in the bedroom. The temperature in the living area is $T_1$, and the temperature in the bedroom is $T_2$.

The thermometer is again coupled to the heater/cooler in such a way that it will activate the heater when the temperature $T$ is below the target value $T_c$, while it will activate the cooler when the temperature is above $T_c$. From here on we assume that $T_c=0$.

Since the two rooms are connected heat will be exchanged between them, and we will assume that the rate at which heat flows from room 1 to room 2 is proportional to the temperature difference $T_1-T_2$. We get the following system of ODE for $T_1$ and $T_2$: \begin{align*} \frac{dT_1}{dt} &= - \kfb T_2 + \kex (T_2-T_1) \\ \frac{dT_2}{dt} &= \kex (T_1-T_2) \end{align*} Here $\kex$ is the rate of heat exchange across the wall.

Write this system in matrix form $\dot\vx = A\vx$, where \[ \vx = \begin{bmatrix} T_1 \\ T_2 \end{bmatrix} \] and find the $2\times 2$ matrix $A$. Then answer the basic questions.

Triple room

\begin{align*} \frac{dT_1}{dt} &= - \kfb T_3 + \kex (T_2-T_1) \\ \frac{dT_2}{dt} &= \kex (T_1-T_2) + \kex (T_3-T_2) \\ \frac{dT_3}{dt} &= \kex (T_1-T_3) \end{align*} Again, write this system in matrix form $\dot\vx = A\vx$, where \[ \vx = \begin{bmatrix} T_1 \\ T_2 \\ T_3 \end{bmatrix} \] and find the $3\times 3$ matrix $A$. Then answer the basic questions.